Coding rounds can be nerve-wracking. You've got 45 minutes, two problems, and a screen staring back at you. But here's the thing: Accenture's coding round isn't designed to trick you — it's designed to test your fundamentals. With the right preparation, you can absolutely crack it. This guide covers real coding problems with solutions in Python, Java, and C++.

Quick Overview: Accenture Coding Round

Topics You Should Focus On

How the Coding Round is Scored

• 1Each question is evaluated against multiple test cases (sample + hidden)
• 2You need to pass all test cases for at least one question
• 3For the second question, partial output is accepted

Real Accenture Coding Questions with Solutions

def differenceofSum(m, n):
    sum_div = 0
    sum_not_div = 0
    for i in range(1, n+1):
        if i % m == 0:
            sum_div += i
        else:
            sum_not_div += i
    return sum_not_div - sum_div

print(differenceofSum(6, 30))  # Output: 285

public static int differenceofSum(int m, int n) {
    int sumDiv = 0, sumNotDiv = 0;
    for (int i = 1; i <= n; i++) {
        if (i % m == 0) sumDiv += i;
        else sumNotDiv += i;
    }
    return sumNotDiv - sumDiv;
}

int differenceofSum(int m, int n) {
    int sumDiv = 0, sumNotDiv = 0;
    for (int i = 1; i <= n; i++) {
        if (i % m == 0) sumDiv += i;
        else sumNotDiv += i;
    }
    return sumNotDiv - sumDiv;
}

def areAnagrams(str1, str2):
    str1 = str1.replace(" ", "").lower()
    str2 = str2.replace(" ", "").lower()
    if len(str1) != len(str2):
        return "No"
    return "Yes" if sorted(str1) == sorted(str2) else "No"

print(areAnagrams("Listen", "Silent"))  # Yes

// Java
import java.util.Arrays;
public static String areAnagrams(String s1, String s2) {
    s1 = s1.replaceAll("\\s","").toLowerCase();
    s2 = s2.replaceAll("\\s","").toLowerCase();
    if (s1.length() != s2.length()) return "No";
    char[] a1 = s1.toCharArray(), a2 = s2.toCharArray();
    Arrays.sort(a1); Arrays.sort(a2);
    return Arrays.equals(a1,a2) ? "Yes" : "No";
}

def nC3(n):
    if n < 3: return 0
    return (n * (n-1) * (n-2)) // 6

def countSockSets(socks):
    freq = {}
    for sock in socks:
        freq[sock] = freq.get(sock, 0) + 1
    total = 0
    for count in freq.values():
        total += nC3(count)
    return total

print(countSockSets([1, 2, 1, 1, 2]))  # 1

def decimalToNBase(n, num):
    symbols = "0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ"
    if num == 0: return "0"
    result = ""
    while num > 0:
        result = symbols[num % n] + result
        num //= n
    return result

print(decimalToNBase(12, 718))  # 4BA

def maxSubarray(arr):
    max_sum = float('-inf')
    current_sum = 0
    for num in arr:
        current_sum += num
        max_sum = max(max_sum, current_sum)
        if current_sum < 0:
            current_sum = 0
    return max_sum

print(maxSubarray([2, -3, 4, -1, 2, 1, -5, 4]))  # 6

7-Step Strategy to Crack Accenture Coding

1. 1
   Master the Basics First: Loops, conditionals, arrays, strings, functions, recursion
2. 2
   Pick One Language and Own It: Stick to C, C++, Java, or Python throughout practice
3. 3
   Practice with Sample Test Cases: Test your code thoroughly before moving on
4. 4
   Think About Edge Cases: Empty inputs, large numbers, negatives, singletons, duplicates
5. 5
   Read Both Problems First: Start with the easier one to build confidence
6. 6
   Write Clean, Readable Code: Meaningful variable names, clear logic
7. 7
   Practice Under Timed Conditions: Simulate 45-minute exam environment at home

Common Mistakes to Avoid

Frequently Asked Questions

The Accenture coding round tests your fundamentals. With consistent practice, smart strategy, and the right mindset, you can absolutely ace it. The problems above are representative — practice them, understand the logic, and you'll be well-prepared. Good luck!